JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

The maximum value of

x^2 y

, subject to constraints

x+y+\sqrt{2 x^2+2 x y+3 y^2}=k

(constant),

x, y \geq 0

View answer and explanation

Correct option: B

\frac{4 k^3}{(3+\sqrt{15})^3}

Option B is correct because it uses AM-GM inequality to find the maximum value of the expression under the given constraint.

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