The monosodium salt of acetylene on treating with dry ${\rm{C}}{{\rm{O}}_2}$ forms:

${\rm{CH}} \equiv {\rm{CCONa}}$

${\rm{CH}} \equiv {\rm{CCOOH}}$

${\rm{CH}} \equiv {\rm{CCONa}}$

NEET UG CHEMISTRY MCQ: HYDROCARBONS

1 Medium

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Application +4 | -1

The monosodium salt of acetylene on treating with dry

\mathrm{C}{\mathrm{O}_2}

forms:

View answer and explanation

Correct option: B

\mathrm{CH} \equiv \mathrm{CCONa}

The correct answer is

\mathrm{CH} \equiv \mathrm{CCONa}

because the monosodium salt of acetylene reacts with carbon dioxide to form sodium acetylide.