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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If for all real triplets (a, b, c)(a,\,b,\,c), f(x)=a+bx+cx2;f\left( x \right) = a + bx + c{x^2}; then ∫01f(x)dx\int_0^1 {f\left( x \right)dx} is equal to
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Correct option: D
16{f(0)+f(1)+4f(12)}\frac{1}{6}\left\{ {f\left( 0 \right) + f\left( 1 \right) + 4f\left( {\frac{1}{2}} \right)} \right\}
Option D is correct because the integral of the given quadratic function can be expressed in terms of the function's values at specific points, matching Simpson's 1/3 rule.

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