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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If the sum of first nn terms of an AP is cn2c n^2, then the sum of squares of these nn terms is
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Correct option: C
n(4n2βˆ’1)c23\frac{n\left(4 n^2-1\right) c^2}{3}
Option C (n(4n2βˆ’1)c23\frac{n(4n^2-1)c^2}{3}) is correct because it is the sum of the squares of the first n terms of the AP, derived from the given sum of the first n terms.

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