JEE MATHEMATICS MCQ: PERMUTATIONS

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An urn contains 3 red pens, 4 green pens and 6 yellow pens. The number of ways of drawing 4 pens from the urn, if atleast one red pen is to be included in the draw, is (all the pens are different from each other)

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Correct option: B

505

Option B (505) is correct because it calculates the total ways to choose 4 pens minus the ways to choose 4 pens without any red pens, which is

{}^{13}C_4 - {}^{10}C_4 = 505

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