If $\tan x=n \tan y, n \in R^{+}$, then maximum value of $\sec ^2(x-y)$ is

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

\tan x=n \tan y, n \in R^{+}

, then maximum value of

\sec ^2(x-y)

View answer and explanation

Correct option: D

\frac{(n+1)^2}{4 n}

Option D (

\frac{(n+1)^2}{4 n}

) is correct because the maximum value of

\sec^2(x-y)

is found by using trigonometric identities and maximizing the expression with respect to

\tan y

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