JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Analyzing +4 | -1

\log _3 27 \cdot \log _x 7=\log _{27} x \cdot \log _7 3

, the least value of

x

, is

View answer and explanation

Correct option: A

7^{-3}

Option A (

7^{-3}

) is correct because solving the logarithmic equation leads to two possible values for x, and

7^{-3}

is the least value.

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