JEE PHYSICS MCQ: WAVE OPTICS

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In a single slit diffraction experiment first minimum for red light

\left( {660\;nm} \right)

coincides with first maximum of some other wavelength

{\lambda}

. The value of

{\lambda}

View answer and explanation

Correct option: A

4400\;\mathop \mathrm{A}\limits^ \circ

Option A (

4400\;\mathop \mathrm{A}\limits^ \circ

) is correct because it is the wavelength calculated by equating the position of the first minimum of red light to the first maximum of the other wavelength.

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