An element $A$ decays into element $C$ by a two step process $A \to B{ + _2}{\rm{H}}{{\rm{e}}^4}$ $B \to C + {2_{ - 1}}\,\,{e^0}$ Then

NEET UG PHYSICS MCQ: NUCLEI

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An element

A

decays into element

C

by a two step process

A \to B{ + _2}\mathrm{H}{\mathrm{e}^4}

B \to C + {2_{ - 1}}\,\,{e^0}

Then

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Correct option: A

A

and

C

are isotopes

Option A (

A

and

C

are isotopes) is correct because in the process, the mass number changes by 4-0 = 4 and the atomic number changes by 2-2 = 0. Therefore, A and C have the same atomic number but different mass numbers, making them isotopes.

More Questions from NUCLEI

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The ratio of the nuclear radii of elements with mass numbers

\mathrm{216}

and

\mathrm{125}

is In a hypothetical fission reaction

{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

The identity of emitted particles

({R})

is: The radius of the nucleus of the atom with A=216 is (take

{R_0}\; = \mathrm{ }1.3fm

) The correct sequence of the increasing wavelength of the given radiation sources is Which of the following nuclear fragments corresponding to nuclear fission between neutron

\left({ }_0^1 \mathrm{n}\right)

and uranium isotope

\left({ }_{92}^{235} \mathrm{U}\right)

is correct: Which of the following has the mass closest in value to that of the positron

1\,\,a.m.u = 931\,\,MeV