JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Understanding +4 | -1

A particle is moving in a circular path. The correct statement out of the following is

View answer and explanation

Correct option: A

Angular momentum will be conserved but linear momentum will not be conserved

Option A (Angular momentum will be conserved but linear momentum will not be conserved) is correct because, in circular motion, the net torque is zero, conserving angular momentum, while the direction of linear momentum continuously changes.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)