JEE PHYSICS MCQ: MOTION IN PLANE

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Analyzing +4 | -1

Given that

\mathrm{\vec A} + \mathrm{\vec B} + \mathrm{\vec C} = 0

. Out of three vectors, two are equal in magnitude and the magnitude of third vector is 

\sqrt 2

times that of either of the two having equal magnitude. Then the angles between vectors are given by

View answer and explanation

Correct option: B

90^\circ ,135^\circ ,135^\circ

Option B (

90^\circ ,135^\circ ,135^\circ

) is correct because it satisfies the vector addition condition with the given magnitudes.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}