Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
1 of 1
Application +4 | -1
The area bounded by the xx-axis, the curve y=f(x)y=f(x) and the lines x=1,x=bx=1, x=b is equal to b2+1−2\sqrt{b^2+1}-\sqrt{2} for all b>1b > 1, then f(x)f(x) is
View answer and explanation
Correct option: D
x1+x2\frac{x}{\sqrt{1+x^2}}
Option D (x1+x2\frac{x}{\sqrt{1+x^2}}) is correct because the derivative of b2+1\sqrt{b^2+1} with respect to bb gives the function f(x)f(x).

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.