If $f\left( 9 \right) = 9,\;f'\left( 9 \right) = 4$, then $\mathop {\lim }\limits_{x \to 9} \frac{{\sqrt {f\left( x \right)} - 3}}{{\sqrt x - 3}}$ equals

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

f\left( 9 \right) = 9,\;f'\left( 9 \right) = 4

, then

\lim\limits_{x \to 9} \frac{{\sqrt {f\left( x \right)} - 3}}{{\sqrt x - 3}}

equals

View answer and explanation

Correct option: A

The correct answer is A (4) because applying L'Hopital's rule and using the given values of f(9) and f'(9) leads to the solution.

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