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JEE CHEMISTRY MCQ: STATES OF MATTER

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Application +4 | -1
Using van der waal's equation, calculate the constant, ' aa ' (atm Ltr⁡2 mole−2\operatorname{Ltr}^2 \mathrm{~mole}^{-2} ) when two moles of a gas confined in a four litre flask exerts a pressure of 11 atm11 \mathrm{~atm} at a temperature of 300 K300 \mathrm{~K}. The value of ' b\mathrm{b} ' is 0.05Litremole 0.05 \mathrm{Litre}^{\text {mole }}.
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Correct option: A
6.5
Option A (6.5) is correct because it is the value of the van der Waals constant 'a' calculated using the given parameters in the van der Waals equation.

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