JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

n

is odd, the sum of

n

terms of the series

1^2-2^2+3^2-4^2+5^2-6^2+\ldots \ldots

, is

View answer and explanation

Correct option: A

\frac{n(n+1)}{2}

Option A (

\frac{n(n+1)}{2}

) is correct because the sum of the series can be simplified to this expression when n is odd.

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