JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

S_n=\sum_{r=0}^n \frac{1}{{ }^n C_r}

and

t_n=\sum_{r=0}^v \frac{r}{{ }^r C_r}

, then

\frac{t_n}{S_s}

is equal to:

View answer and explanation

Correct option: D

\frac{1}{2} n

Option D (

\frac{1}{2} n

) is correct because by using the property

{ }^n C_r = { }^n C_{n-r}

and manipulating the summation, we can show that

\frac{t_n}{S_n} = \frac{n}{2}

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