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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If f(x)f(x) is a function satisfying f(x+y)=f(x)f(y),∀x,y∈Nf(x+y)=f(x) f(y), \forall x, y \in N such that f(1)=3f(1)=3 and ∑x=1nf(x)=120\sum_{x=1}^n f(x)=120. Then, the value of nn is
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Correct option: A
4
Option A (4) is correct because by using the given functional equation and the sum of the function values, we can determine that f(x) = 3^x, and solving the sum equation gives n = 4.

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