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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
In the relation p=αβ  e−αzkθ,  pp = \frac{\mathrm{\alpha }}{\mathrm{\beta }}\mathrm{\;}{\mathrm{e}^{ - \frac{{\alpha z}}{{k\mathrm{\theta }}}}},\mathrm{\;}p , is the pressure, z the distance, k is Boltzmann constant and θ\theta is the temperature, the dimensional formula of β\beta will be
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Correct option: A
[M0L2T0]\left[ {{\mathrm{M}^0}{\mathrm{L}^2}{\mathrm{T}^0}} \right]
Option A ([M⁰L²T⁰]) is correct because the exponent in the exponential term must be dimensionless, allowing us to determine the dimensions of β.

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