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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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The distance between a proton and electron both having a charge

1.6 \times {10^{ - 19}}coulomb,

, of a hydrogen atom is

{10^{ - 10}}metre.

. The value of intensity of electric field produced on electron due to proton will be

View answer and explanation

Correct option: D

1.44 \times {10^{11}}N/C

Option D (

1.44 imes {10^{11}}N/C

) is correct because it's the electric field intensity calculated using Coulomb's law at the given distance.

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