JEE CHEMISTRY MCQ: REDOX REACTIONS

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The equivalent weight of a reductant or an oxidant is given by :

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Correct option: A

\mathrm{Eq}\mathrm{.wt}\mathrm{.} = \frac{{\mathrm{mol}\mathrm{.weight\,\, of\,\, reductant\,\, or\,\, oxidant}}}{{\begin{array}{cccccccccccccccccccc} {\mathrm{no}\mathrm{.of\,\, electrons\,\, lost\,\, or\,\, gained \,\,by}}\\ {1{\rm{molecule\,\, of\,\, reductant\,\, or\,\, oxida

Option A is correct because it accurately defines the equivalent weight of a reductant or oxidant as the molecular weight divided by the number of electrons lost or gained per molecule.

More Questions from REDOX REACTIONS

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The oxidation number of

\mathrm{H}

in sodium hydride is A reagent, which can decrease the oxidation number of an element, is called Consider the following decomposition reaction

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

In the above reaction, Assertion (A):

\mathrm{HNO}_3

acts as oxidizing agent.

Reason (R): Oxidation no. of nitrogen is +5, no increase in oxidation no. beyond +5 can occur. The oxidation no. of

\mathrm{HNO}_3

can only decrease. Assertion :- Bromide ion is serving as a reducing agent in the reaction.

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

Reason :- Oxidation number of

\mathrm{Br}

increases from

-1

+5.

A substance, that by its sharp colour change indicates the completion of reaction is known as :