If $\mathop {\lim }\limits_{x \to 1} \frac{{a{x^2} + bx + c}}{{{{\left( {x - 1} \right)}^2}}} = 2,\;$ then (a, b, c) is

JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to 1} \frac{{a{x^2} + bx + c}}{{{{\left( {x - 1} \right)}^2}}} = 2,\;

then (a, b, c) is

View answer and explanation

Correct option: A

\left( {2, - 4,2} \right)

Option A ((2, -4, 2)) is correct because for the limit to exist, the numerator must be equivalent to 2(x-1)², leading to a=2, b=-4, and c=2.

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