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NEET UG CHEMISTRY MCQ: SOLID STATE

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Which of the following expressions is correct in case of a CsCl\mathrm{CsCl} unit cell (edge length ' aa ')?
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Correct option: B
rCs++rClβˆ’=32a\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\sqrt{3}}{2} \mathrm{a}
Option B is correct because in a CsCl unit cell, the Cs+ ion is at the body center and touches the Cl- ions at the corners along the body diagonal, which is equal to 2(rCs++rClβˆ’)=3a2(r_{Cs^+} + r_{Cl^-}) = \sqrt{3}a.

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