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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1

If

S=(1)(1 !)+(2)(2 !)+(3)(3 !)+\ldots+n(n !)

, then

View answer and explanation

Correct option: A

\frac{S+1}{n !} \in

integer

Option A (

\frac{{S+1}}{{n !}} \in

integer) is correct because the expression S can be simplified to (n+1)! - 1, making (S+1) equal to (n+1)!, which is divisible by n!.

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