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NEET UG PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1
In young’s two slit experiment the distance between the two coherent sources is 2  mm2\;mm and the screen is at a distance of 1  m1\;m. If the fringe width is found to be 0.03  cm0.03\;cm, then the wavelength of the light used is
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Correct option: D
6000A∘6000\mathop \mathrm{A}\limits^ \circ
Option D (6000A∘6000\mathop \mathrm{A}\limits^ \circ) is correct because it is calculated using the formula for fringe width in Young's double-slit experiment.

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