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JEE CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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Analyzing +4 | -1
Consider the reaction:

(i) (CH3)2CH−CH2Br⟶C2H5OH(CH3)2CH−CH2OC2H5+HBr\left({CH}_3\right)_2 {CH}-{CH}_2 {Br} \stackrel{{C}_2 {H}_5 {OH}}{\longrightarrow}\left({CH}_3\right)_2 {CH}-{CH}_2 {OC}_2 {H}_5+{HBr}

(ii) (CH3)2CH−CH2Br⟶C2H5O−(CH3)2CH−CH2OC2H5+Br−\left({CH}_3\right)_2 {CH}-{CH}_2 {Br} \stackrel{{C}_2 {H}_5 {O}^{-}}{\longrightarrow}\left({CH}_3\right)_2 {CH}-{CH}_2 {OC}_2 {H}_5+{Br}^{-}

The mechanisms of reaction (i) and (ii) are respectively :-
View answer and explanation
Correct option: D
SN2{S}{{N}^2} and SN2{S}{{N}^2}
Option B (SN1{S}{{N}^1} and SN2{S}{{N}^2}) is correct because reaction (i) with C2H5OHC_2H_5OH favors SN1S_N1 due to the formation of a carbocation, while reaction (ii) with C2H5O−C_2H_5O^- favors SN2S_N2 due to the strong nucleophile.

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