JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\theta_1

and

\theta_2

are two values lying in

[0,2 \pi]

for which

\tan \theta=\lambda

, then

\tan \frac{\theta_1}{2} \tan \frac{\theta_2}{2}

is equal to

View answer and explanation

Correct option: B

-1

Option B (-1) is correct because the product of the roots of the quadratic equation in

\tan \frac{{\theta}}{{2}}

is -1.

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