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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The sum ∑k=120k12k\sum_{k=1}^{20} k \frac{1}{2^{k}} is equal to :
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Correct option: C
2−112192-\frac{11}{2^{19}}
Option C (2-11219\frac{11}{2^{19}}) is correct because it is the result of summing the given series using the method of differences.

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