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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If Hn=1+12+13+…+1nH_n=1+\frac{1}{2}+\frac{1}{3}+\ldots+\frac{1}{n}, then value of 1+32+53+…+2n−1n1+\frac{3}{2}+\frac{5}{3}+\ldots+\frac{2 n-1}{n} is
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Correct option: B
2n−Hn2 n-H_n
Option B is correct because the given expression can be simplified using the definition of H_n.

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