JEE MATHEMATICS MCQ: COMBINATIONS

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Application +4 | -1

A man

X

has 7 friends, 4 of them are ladies and 3 are men. His wife

Y

also has 7 friends, 3 of them are ladies and 4 are men. Assume and

Y

have no common friends. Then, the total number of ways in which

X

and

Y

together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of

X

and

Y

are in this party, is

View answer and explanation

Correct option: A

485

Option A (485) is correct because it is the sum of all possible combinations of selecting 3 ladies and 3 men from X and Y's friends.

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m \times n

m

n

A

B

{\;^{n + 2}}{C_8}:{\;^{n - 2}}{P_4} = \frac{{57}}{{16}}

n