JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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Application +4 | -1

\cos \,\,20^\circ = k

and

cos\;\,x = 2{k^2} - 1

, then the possible values of

x

between

0^\circ

and

360^\circ

are

View answer and explanation

Correct option: C

40^\circ

and

320^\circ

Option C (

40^\circ

and

320^\circ

) is correct because using the double angle formula for cosine, we find that cos(x) = cos(40), leading to x = 40 and x = 360 - 40 = 320.

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