JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Medium

1 of 1

Application +4 | -1

\sin A-\sqrt{6} \cos A=\sqrt{7} \cos A

, then

\cos A+\sqrt{6} \sin A

is equal to

View answer and explanation

Correct option: B

\sqrt{ } 7 \sin A

Option B (

\sqrt{7} \sin A

) is correct because by manipulating the given equation, we can express

\cos A

in terms of

\sin A

and then substitute to find the value of

\cos A + \sqrt{6} \sin A

More Questions from TRIGONOMETRY RATIOS

Practice All Chapter MCQs →

\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=