JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

Consider two G.Ps.

2,2^2, 2^3, \ldots

and

4,4^2, 4^3, \ldots

of 60 and

n

terms respectively. If the geometric mean of all the

60+n

terms is

(2)^{\frac{225}{8}}

then

\sum\limits_{k = 1}^n {k(n - k)}

is equal to

View answer and explanation

Correct option: C

1330

Option C (1330) is correct because after calculating the value of n using the geometric mean formula, the summation simplifies to 1330.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}