If ${{\rm{H}}_2}{\rm{S}}$ is passed through an acidified ${{\rm{K}}_2}{\rm{C}}{{\rm{r}}_2}{{\rm{O}}_7}$solution, the colour of the solution :

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Understanding +4 | -1

{\mathrm{H}_2}\mathrm{S}

is passed through an acidified

{\mathrm{K}_2}\mathrm{C}{\mathrm{r}_2}{\mathrm{O}_7}

solution, the colour of the solution :

View answer and explanation

Correct option: C

Will change to dark green

Option C (Will change to dark green) is correct because

Cr^{6+}

is reduced to

Cr^{3+}

which is green in color.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.