Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Application +4 | -1
The coefficient of xn{x^n} in the series

1+a+bx1!+(a+bx)22!+(a+bx)33!+…,1 + \frac{{a + bx}}{{1!}} + \frac{{{{\left( {a + bx} \right)}^2}}}{{2!}} + \frac{{{{\left( {a + bx} \right)}^3}}}{{3!}} + \ldots , is
View answer and explanation
Correct option: C
eabnn  !{e^a}\frac{{{b^n}}}{{n\;!}}
Option C (eabnn  !{e^a}\frac{{{b^n}}}{{n\;!}}) is correct because the coefficient of xn{x^n} in the given series is found by expanding the exponential function.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.