JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The equation of curves which intersect the hyperbola

x y=4

at an angle

\pi / 2

View answer and explanation

Correct option: C

y^2-x^2=C

Option C (

y^2-x^2=C

) is correct because it represents the orthogonal trajectories to the given hyperbola.

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y=y(x)

\left(3 y^{2}-5 x^{2}\right) y d x+2 x\left(x^{2}-y^{2}\right) d y=0

y(1)=1

\left|(y(2))^{3}-12 y(2)\right|

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{x^2} + {y^2} = 1

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x = A\cos 4t + B\sin 4t,

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\frac{d y}{d x}=y+7

y_{1}(0)=0

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

\alpha>0, \beta>0

\gamma>0

\lim \limits_{{x \rightarrow \infty}} y(t)