JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

Let

L=\lim \limits_{{n \rightarrow \infty}} \frac{1}{n^3} \sum\limits_{{k=1}}^n k^2 e^{\frac{k}{n}}

, then find the value of

e-L

View answer and explanation

Correct option: A

Option A (2) is correct because the limit L is evaluated as a definite integral, and then e-L is calculated.

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