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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
The coefficient of x50x^{50} in the binomial expansion of
(1+x)1000+x(1+x)999+x2(1+x)998+….+x1000 is: \begin{array}{lr} (1+x)^{1000}+x(1+x)^{999}+x^{2}(1+x)^{998}+\ldots . \\ +x^{1000} \text { is: } \end{array}

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Correct option: D
(1001)!(50)!(951) ! \frac{(1001) !}{(50) !(951) \text { ! }}
Option D ((1001)!(50)!(951)!\frac{{(1001) !}}{{(50) !(951) !}}) is correct because by simplifying the given series and finding the coefficient of x50x^{50} in the resulting binomial expansion, we get (1001)!(50)!(951)!\frac{{(1001) !}}{{(50) !(951) !}}.

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