JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

The equation of a circle is given by

x^2+y^2=a^2

, where

a

is the radius. If the equation is modified to change the origin other than

(0,0)

, then find out the correct dimensions of

A

and

B

in a new equation

(x-A t)^2+\left(y-\frac{t}{B}\right)^2=a^2

. The dimension of

t

is given as

\left[\mathrm{T}^{-1}\right]

View answer and explanation

Correct option: A

A=[L T], B=\left[L^{-1} T^{-1}\right]

Option A (

A=[L T], B=[L^{-1} T^{-1}]

) is correct because it satisfies the dimensional homogeneity in the given equation.

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