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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

1 Hard
1 of 1
Application +4 | -1
In finding out refractive index of glass slab the following observations were made through travelling microscope 50 vernier scale division = 49 MSD; 20 divisions on main scale in each cm\mathrm{cm}
For mark on paper
MSR=8.45 cm,VC=26\mathrm{MSR}=8.45 \mathrm{~cm}, \mathrm{VC}=26
For mark on paper seen through slab
MSR=7.12 cm,VC=41\mathrm{MSR}=7.12 \mathrm{~cm}, \mathrm{VC}=41
For powder particle on the top surface of the glass slab
MSR⁡=4.05 cm,VC=1\operatorname{MSR}=4.05 \mathrm{~cm}, \mathrm{VC}=1
(MSR=(\mathrm{MSR}= Main Scale Reading, VC=\mathrm{VC}= Vernier Coincidence)
Refractive index of the glass slab is:
View answer and explanation
Correct option: A
1.42
Option A (1.42) is correct because the refractive index is calculated by dividing the real depth by the apparent depth.

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