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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If ∫0π2ln⁡∣tan⁡x+cot⁡x∣dx=λln⁡2\int\limits_{0}^{\frac{\pi}{2}} \ln |\tan x+\cot x| d x=\lambda \ln 2, then λ\lambda equals
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Correct option: B
π\pi
Option B (π\pi) is correct because the integral simplifies to πln⁡2\pi \ln 2 after using trigonometric identities and properties of logarithms, thus λ=π\lambda = \pi.

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