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JEE CHEMISTRY MCQ: CHEMICAL KINETICS

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For the reaction,

H2(g)+Br2(g)β†’2HBr(g){\mathrm{H}_2}\left( \mathrm{g} \right) + \mathrm{B}{\mathrm{r}_2}\left( \mathrm{g} \right) \to 2\mathrm{HBr}\left( \mathrm{g} \right)

The experimental data suggest

rate=k[H2][Br2]1/2\mathrm{rate} = k\left[ {{\mathrm{H}_2}} \right]{\left[ {\mathrm{B}{\mathrm{r}_2}} \right]^{1/2}}

the molecularity and order of the reaction are respectively
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Correct option: D
2,322,\frac{3}{2}
Option D (2,322,\frac{3}{2}) is correct because molecularity is the number of reacting species in an elementary reaction (2 in this case), and the order of the reaction is the sum of the exponents in the rate law (1+12=321 + \frac{1}{2} = \frac{3}{2}).

More Questions from CHEMICAL KINETICS

Practice All Chapter MCQs β†’
The reaction A2+B2β†’2AB\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB} follows the mechanism

A2β‡Œkβˆ’1k1A+AΒ (fast)Β A+B2β†’k2AB+BΒ (slow)Β A+Bβ†’ABΒ (fast)Β \begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

The overall order of the reaction is:
For the first order reaction with the rate constant kk, which expression gives the rate half-life period? (Initialconc.=a)(Initial\mathrm{ }conc.\mathrm{ } = a) Which of the following is a zero order reaction? For a certain reaction involving a single reactant, it is found that C0TC_0 \sqrt{T} is constant, where C0C_0 is the initial concentration of the reactant and TT is the half-life. What is the order of the reaction? Arrhenius equation is The energy of activation for an uncatalysed reaction is 100 kJ/mol.100 \mathrm{~kJ/mol}. Presence of a catalyst lowers the energy of activation by 75%75 \%. The log⁑10K2K1\log _{10} \frac{K_2}{K_1} of the ratio of rate constant of catalysed and uncatalysed reactions at 27∘C27^{\circ} \mathrm{C} is?

Assume the frequency factor is same for both reactions. (Given 2.303Γ—8.314=19.1472.303 \times 8.314=19.147)
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