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NEET UG CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

1 Hard
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Application +4 | -1
α-chloropropionic acid on treatment with alcoholic KOH followed by acidification gives:
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Correct option: B
CH2=CH−COOH\mathrm{C}{\mathrm{H}_2} = CH-COOH
Option B (CH2=CH−COOH\mathrm{C}{\mathrm{H}_2} = CH-COOH) is correct because the reaction sequence results in dehydrohalogenation followed by the formation of an alpha, beta-unsaturated acid.

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