JEE MATHEMATICS MCQ: SET THEORY

1 Easy

1 of 1

Analyzing +4 | -1

A = \left\{ {p:p = \frac{{\left( {n + 2} \right)\left( {2{n^5} + 3{n^4} + 4{n^3} + 5{n^2} + 6} \right)}}{{{n^2} + 2n}},n,p \in {{\text{Z}}^ + }} \right\}

then the number of elements in the set

A

, is

View answer and explanation

Correct option: C

Option C (4) is correct because the expression simplifies to

p = 2n^4 + 3n^3 + 4n^2 + 5n + \frac{6}{n}

, and

p

is an integer only when

n

is a factor of 6, giving 4 possible values.

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S

2 a_1 a_2 a_3 \ldots . . a_{2006}

a_1, a_2, a_3, \ldots ., a_{2006}

S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

c N=\{c N: n \in N\}

b N \cap c N=d N

a, b, c \in N

b, c

A=\{x: x

\}

B=\{x: x

A-B

F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

40 \%

A, 20 \%

10 \%

C

A

C

4 \%

A

C

2 \%

A