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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
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Application +4 | -1
The remainder when x=1!+2!+3!+4!+…+100x = 1! + 2! + 3! + 4!+\ldots+100 ! is divided by 240, is
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Correct option: A
153
Option A (153) is correct because for factorials greater than 5!, the remainder when divided by 240 is 0, so we only need to consider the sum of the first five factorials.

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