The major product $P$ in the following reaction is $C{H_3} - C{H_2}N{H_2}\xrightarrow[{0 - {5^{\rm{o}}}C}]{{NaN{o_2},\,\,HCl}}A\xrightarrow{{{H_2}O}}P({\rm{Major}})$

NEET UG CHEMISTRY MCQ: AMINES

1 Medium

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Application +4 | -1

The major product

P

in the following reaction is

C{H_3} - C{H_2}N{H_2}\xrightarrow[{0 - {5^\mathrm{o}}C}]{{NaN{o_2},\,\,HCl}}A\xrightarrow{{{H_2}O}}P(\mathrm{Major})

View answer and explanation

Correct option: A

C{H_3} - C{H_2} - OH

Option A (

C{H_3} - C{H_2} - OH

) is correct because the reaction of ethylamine with

NaN{O_2}

and

HCl

forms an unstable diazonium salt, which then reacts with water to yield ethanol.