The binding energies per nucleon for a deuteron and an $\alpha {\rm{ - }}$ particle are ${x_1}\,\,\,{\rm{and}}\,\,\,\,\,{x_2}$ respectively. What will be the energy Q released in the reaction ${}_1{H^2} + {}_1{H^2} \to {}_2H{e^4} + Q$

JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

The binding energies per nucleon for a deuteron and an

\alpha \mathrm{ - }

particle are

{x_1}\,\,\,\mathrm{and}\,\,\,\,\,{x_2}

respectively. What will be the energy Q released in the reaction

{}_1{H^2} + {}_1{H^2} \to {}_2H{e^4} + Q

View answer and explanation

Correct option: B

4({x_2} - {x_1})

Option B (

4({x_2} - {x_1})

) is correct because the energy released is the difference between the binding energies of the products and the reactants.