JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

Efficiency of a heat engine is

\eta=0.4

and the temperature of the source is

227^{\circ} \mathrm{C}

. If the temperature of source and sink increased by

100^{\circ} \mathrm{C}

, then the efficiency of a modified heat engine is

View answer and explanation

Correct option: B

1 / 3

Option B (

1/3

) is correct because the efficiency of the modified heat engine is calculated using the new source and sink temperatures after the increase.

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