The maximum value of $27^{\cos 2 x} 81^{\sin 2 x}$ is

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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The maximum value of

27^{\cos 2 x} 81^{\sin 2 x}

View answer and explanation

Correct option: B

3^5

Option B (

3^5

) is correct because the maximum value is obtained when

3 \cos 2x + 4 \sin 2x

is maximized, which occurs at

\sqrt{3^2 + 4^2} = 5

, resulting in

3^5

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