$M$ is the molecular weight of ${\rm{KMn}}{{\rm{O}}_4}.$ The equivalent weight of ${\rm{KMn}}{{\rm{O}}_4}$ when it is converted into ${{\rm{K}}_2}{\rm{Mn}}{{\rm{O}}_4}$ is :

NEET UG CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Easy

1 of 1

Application +4 | -1

M

is the molecular weight of

\mathrm{KMn}{\mathrm{O}_4}.

The equivalent weight of

\mathrm{KMn}{\mathrm{O}_4}

when it is converted into

{\mathrm{K}_2}\mathrm{Mn}{\mathrm{O}_4}

is :

View answer and explanation

Correct option: A

M

Option A (

M

) is correct because when

KMnO_4

is converted to

K_2MnO_4

, the oxidation state of Mn changes from +7 to +6, a change of 1. Therefore, the equivalent weight is M/1 = M.