The value of $\cot \frac{\pi }{{24}}$ is

$3\sqrt 2 - \sqrt 3 - \sqrt 6 $

JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

The value of

\cot \frac{\pi }{{24}}

View answer and explanation

Correct option: B

\sqrt 2 + \sqrt 3 + 2 + \sqrt 6

Option B (

\sqrt 2 + \sqrt 3 + 2 + \sqrt 6

) is correct because it is the simplified value of cot(π/24) after applying trigonometric identities.

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